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From Tao Xiao <xiaotao.cs....@gmail.com>
Subject Re: What does this line mean in hbase shell?
Date Tue, 11 Feb 2014 09:42:53 GMT
Ok, I see, thanks ramkrishna.


2014-02-11 17:25 GMT+08:00 ramkrishna vasudevan <
ramkrishna.s.vasudevan@gmail.com>:

> Hi
>
> It describes the (x) rows describes the number of items retrieved to
> display in the output and xxxx seconds says the time taken for displaying
> it.
> Incase of puts as there are not rows to be retrieved and displayed the (x)
> rows remains 0, but the xxx seconds says the time it took for doing that
> operation. If the time calculation is accurate or not am not sure on that.
>  Need to see how it is calculated.
> Does this answer you question?
>
> Regards
> Ram
>
>
> On Tue, Feb 11, 2014 at 2:48 PM, Tao Xiao <xiaotao.cs.nju@gmail.com>
> wrote:
>
> > I executed some commands in hbase's shell and got the following results:
> >
> > hbase(main):014:0> list
> > TABLE
> >
> > testtable
> >
> > 1 row(s) in 0.0180 seconds          ### what does "1 row(s)" mean?
> >
> > hbase(main):015:0> count 'testtable'
> > Current count: 1000, row: row-999
> >
> > 1000 row(s) in 0.3300 seconds     ### indeed  we have 1000 rows in
> > testtable
> >
> > hbase(main):017:0> create 'newtable', 'cf'
> > 0 row(s) in 1.1450 seconds
> >
> > hbase(main):018:0> put 'newtable', 'row1', 'cf:A', 'value1'
> > 0 row(s) in 0.0120 seconds          ### what does "0 row(s)" mean?
> >
> > hbase(main):019:0> put 'newtable', 'row2', 'cf:A', 'value2'
> > 0 row(s) in 0.0080 seconds
> >
> > we can see that the shell printed results ending with "xx row(s) in xxx
> > seconds", what does this mean ?
> >
>

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