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From Georg Sorst <georg.so...@gmail.com>
Subject Re: Using function queries for faceting
Date Tue, 04 Apr 2017 14:43:15 GMT
Hi Mikhail,

copying the default field was my first attempt as well - however, the
system in total has over 50.000 users which may have an individual price on
every product (even though they usually don't). Still, with the copying
approach this results in every document having 50.000 price fields. Solr
completely chokes trying to import this data.

Best,
Georg

Mikhail Khludnev <mkhl@apache.org> schrieb am Di., 4. Apr. 2017 um
15:28 Uhr:

> Hello Georg,
> You can probably use {!frange} and  and a few facet.query enumerating price
> ranges, but probably it's easier to just copy default price across all
> empty price groups in index time.
>
>
> On Tue, Apr 4, 2017 at 1:14 PM, Georg Sorst <georg.sorst@gmail.com> wrote:
>
> > Hi list!
> >
> > My documents are eCommerce items. They may have a special price for a
> > certain group of users, but not for other groups of users; in that case
> the
> > default price should be used. So the documents look like something like
> > this:
> >
> > item:
> >   id: 1
> >   price_default: 11.5
> >   price_group1: 11.2
> > item:
> >   id: 2
> >   price_default: 12.3
> >   price_group2: 12.5
> >
> > Now when I want to fetch the documents and display the correct price for
> > group1 I can use 'fl=def(price_group1,price_default)'. Works like a
> charm!
> > It will return price_group1 for document 1 and price_default for document
> > 2.
> >
> > Is there a way to do this for faceting as well? I've unsuccessfully
> tried:
> >
> > * facet.field=def(price_group1,price_default)
> > * facet.field=effective_price:def(price_group1,price_default)
> > * facet.field={!func}def(price_group1,price_default)
> > * facet.field={!func}effective_price:def(price_group1,price_default)
> > * json.facet={price:"def(price_group1,price_default)"}
> >
> > I'm fine with either the "old" facet API or the JSON facets.Any ideas?
> >
> > Thanks!
> > Georg
> >
>
>
>
> --
> Sincerely yours
> Mikhail Khludnev
>

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