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From Jake Mannix <jake.man...@gmail.com>
Subject Re: understanding vectors
Date Mon, 14 Jan 2013 17:58:41 GMT
I think you mean 0.7, right?  Can you see if you get the same behavior in
svn trunk?


On Mon, Jan 14, 2013 at 9:21 AM, Koert Kuipers <koert@tresata.com> wrote:

> i am using version mahout 7.0
>
> On Mon, Jan 14, 2013 at 10:15 AM, Ted Dunning <ted.dunning@gmail.com>
> wrote:
>
> > Which version are you using?
> >
> > (this misbehavior sounds familiar)
> >
> > iterator() should return all values.
> >
> > iterateNonZero() is allowed to skip zeros.
> >
> > On Mon, Jan 14, 2013 at 6:11 AM, Koert Kuipers <koert@tresata.com>
> wrote:
> >
> > > i am looking at the iterators for DenseVector,
> RandomAcccessSparseVector
> > > and SequentialAccessSparseVector.
> > >
> > > for both DenseVector and RandomAcccessSparseVector the iterator seems
> to
> > > return all values, including the missing zero values.
> > > for SequentialAccessSparseVector the iterator also returns all values,
> > but
> > > only up to the last non-missing value!
> > >
> > > is this by design? what is a vector iterator supposed to return
> exactly?
> > i
> > > can't see a logical pattern/consistency. see examples below.
> > > thanks! koert
> > >
> > > scala> val x = new org.apache.mahout.math.RandomAccessSparseVector(5)
> > > x: org.apache.mahout.math.RandomAccessSparseVector = {}
> > >
> > > scala> x.set(3, 1.0)
> > >
> > > scala> for (item <- x.iterator.asScala) println((item.index, item.get))
> > > (0,0.0)
> > > (1,0.0)
> > > (2,0.0)
> > > (3,1.0)
> > > (4,0.0)
> > >
> > > scala> val y = new
> org.apache.mahout.math.SequentialAccessSparseVector(5)
> > > y: org.apache.mahout.math.SequentialAccessSparseVector = {
> > >
> > > scala> y.set(3, 1.0)
> > >
> > > scala> for (item <- y.iterator.asScala) println((item.index, item.get))
> > > (0,0.0)
> > > (1,0.0)
> > > (2,0.0)
> > > (3,1.0)
> > >
> >
>



-- 

  -jake

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