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From "Robbie Gemmell (Commented) (JIRA)" <j...@apache.org>
Subject [jira] [Commented] (QPID-3836) no-local does not work for Qpid 0-10 JMS client
Date Mon, 13 Feb 2012 17:48:59 GMT

    [ https://issues.apache.org/jira/browse/QPID-3836?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=13207008#comment-13207008

Robbie Gemmell commented on QPID-3836:

I think the title is perhaps a little misleading, given the number of tests running that show
it does work to an extent. Perhaps 'doesn't work when used on queues not originally declared
no-local' would be clearer. The BURL usage may always send the queue declare, but redeclaring
a queue that exists wont make it no-local.

The client currently only sends the no-local argument during queue creation as you mentioned,
but there is support in the protocol for adding arguments to subscriptions so it could potentially
be added there too (The protocol actually has a no-local field on the file and stream consume
methods, so why it doesn't on the standard subscribe method I'm not sure)
> no-local does not work for Qpid 0-10 JMS client
> -----------------------------------------------
>                 Key: QPID-3836
>                 URL: https://issues.apache.org/jira/browse/QPID-3836
>             Project: Qpid
>          Issue Type: Bug
>          Components: Java Client
>    Affects Versions: 0.12
>            Reporter: Rajith Attapattu
>            Assignee: Rajith Attapattu
>             Fix For: 0.15
> If no-local is set to true when create a consumer or a durable subscriber, messages published
by the same connection should not be seen by this consumer.
> Currently due to a bug no-local is not passed correctly when creating the subscription
> All though this works for Topics and Queues created when this information is available,
not sure how this should be handled when subscribing to an already existing queue.
> AKAIK the no-local argument is passed on during queue-declare. Perhaps there is also
a way to pass this on when creating a subscription ?
> (I will update the description when I find the answer to the above question). 

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