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From Eric Brown <EBr...@2wire.com>
Subject RE: Firewall tunneling, question still open !
Date Tue, 08 Jan 2002 17:59:20 GMT
I haven't looked at more recent JVMs, but as of JDK 1.1, you could not get
the JVM to do 407 based HTTP proxy authentication. I think you have to use
somebody elses HTTP client. I imagine there is a way to hook XMLRPC to it.
There are several HTTP clients out there, but I don't know which one would
be easiest to use. Sorry.

Eric

Eric Brown
2Wire.Inc
Server Engineering Manager
p. 408.503.1060

Want to share your DSL or cable connection with all the computers in your
house?  Check out 2Wire's HomePortal at http://www.2wire.com/products.


-----Original Message-----
From: Olivier Sarrat [mailto:olivier_sarrat@hotmail.com] 
Sent: Tuesday, January 08, 2002 9:46 AM
To: rpc-user@xml.apache.org
Subject: RE: Firewall tunneling, question still open !

Thanks Eric for your fast answer, but I knew already about that system 
properties stuff... You can only set the hostname and port of the proxy 
server through them, but you can't set the login/password.

So, the question is still open !


>The JVM itself has some system properties you can set to go through
>application level firewalls (i.e. http proxy or socks). I don't remember
>what the exact settings are, but you'd run something like java
>-Dhttp.proxy=blablabla.
>
>Eric
>
>
>Hi !
>
>Does anyone know how to go through a firewall without rewriting a complete
>XML-RPC client ?
>
>I manage of course to set the System properties with the hostname and port
>of the proxy server.. but there's no method in XmlRpcClient to pass the
>login/password.. I've tried setBasicAuthentification, but it doesn't 
>wotk...
>
>Has anyone any idea ?
>
>Cheers !
>
>Olivier Sarrat.
>
>




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