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Q: How do you reduce 7 6 over 6?

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6/7

6/7

the GCF is 5 so IF YOU REDUCE IT YOUL'LL GET 6/76/7

There is no way to reduce 7 over 8 because it is already in simplest form.

Neither, Both fractions reduce to 3/7, so they are equal.

So the problem is 7/9 divided by 3/6. you can reduce 3/6 to 1/2 so now your equation is 7/9 divided by 1/2 you do the reciprocal and you get 7/9 multiplied by 2/1 and you get 14/9, or 1 5/9

6 over 7 minus 5 over 7 is 1 over 7.

You cannot reduce 23/6. 23 is a prime number.

No

No; 7 / 20 is irreducible.

That's the same as 6/7 x 6/7 = 36/49

You mean simplify then yes, it would be reduce to 3 over 5.

It is 7 over 6

It is 7 over 6.

No, because if you reduce 12/36 then you get 3 and if you reduce 5/7 you get a decimal, not 3.

6/7 * 6/13 = (6*6)/(7*13) = 36/91

6/9 * 7/6 = 1/9 * 7/1 = 7/9

6 over 7

7/8.5 ÷ 6= 0.82 ÷ 6 = 0.136

One.

3 over 7, 6 over 11, 7 over 10.

6/7 - 6/25 = 6*(1/7 - 1/25) = 6*(25-7)/(7*25) = 6*18/(7*25) = 108/175

9,18,27,36,45,54,63,70 and count the numbers as 1 2 3 4 5 6 7 8 9 how many 9s

6 over 7 is greater!

6/7 × 7/11 = (6×7)/(11×11) = 42/121