Actually I think it is possibly that an user/developer needs the
standardized features with population mean and std in some cases. It would
be better if StandardScaler can offer the option to do that.
Holden Karau wrote
> Hi Gilad,
>
> Spark uses the sample standard variance inside of the StandardScaler (see
> https://spark.apache.org/docs/2.0.2/api/scala/index.html#org.apache.spark.mllib.feature.StandardScaler
> ) which I think would explain the results you are seeing you are seeing. I
> believe the scalers are intended to be used on larger sized datasets You
> can verify this yourself doing the same computation in Python and see the
> scaling using the sample deviation result in the values you are seeing
> from
> Spark.
>
> Cheers,
>
> Holden :)
>
>
> On Sun, Jan 8, 2017 at 12:06 PM, Gilad Barkan <
> gilad.barkan@
> >
> wrote:
>
>> Hi
>>
>> It seems that the output of MLlib's *StandardScaler*(*withMean=*True,
>> *withStd*=True)are not as expected.
>>
>> The above configuration is expected to do the following transformation:
>>
>> X > Y = (XMean)/Std  Eq.1
>>
>> This transformation (a.k.a. Standardization) should result in a
>> "standardized" vector with unitvariance and zeromean.
>>
>> I'll demonstrate my claim using the current documentation example:
>>
>> >>> vs = [Vectors.dense([2.0, 2.3, 0]), Vectors.dense([3.8, 0.0,
>> 1.9])]>>> dataset = sc.parallelize(vs)>>> standardizer =
>> StandardScaler(True, True)>>> model = standardizer.fit(dataset)>>>
result
>> = model.transform(dataset)>>> for r in result.collect(): print r
>> DenseVector([0.7071, 0.7071, 0.7071]) DenseVector([0.7071,
>> 0.7071, 0.7071])
>>
>> This result in std = sqrt(1/2) foreach column instead of std=1.
>>
>> Applying Standardization transformation on the above 2 vectors result in
>> the following output
>>
>> DenseVector([1.0, 1.0, 1.0]) DenseVector([1.0, 1.0, 1.0])
>>
>>
>> Another example:
>>
>> Adding another DenseVector([2.4, 0.8, 3.5]) to the above we get a 3 rows
>> of DenseVectors:
>> [DenseVector([2.0, 2.3, 0.0]), DenseVector([3.8, 0.0, 1.9]),
>> DenseVector([2.4, 0.8, 3.5])]
>>
>> The StandardScaler result the following scaled vectors:
>> [DenseVector([1.12339, 1.084829, 1.02731]), DenseVector([0.792982,
>> 0.88499, 0.057073]), DenseVector([0.330409, 4
>> 0.19984, 0.970241])
>>
>> This result has std=sqrt(2/3)
>>
>> Instead it should have resulted other 3 vectors that form std=1 for each
>> column.
>>
>> Adding another vector (4 total) results in 4 scaled vectors that form
>> std= sqrt(3/4) instead of std=1
>>
>> I hope all the examples help to make my point clear.
>>
>> I hope I don't miss here something.
>>
>> Thank you
>>
>> Gilad Barkan
>>
>>
>>
>>
>>
>>
>
>
> 
> Cell : 4252338271
> Twitter: https://twitter.com/holdenkarau

LiangChi Hsieh  @viirya
Spark Technology Center
http://www.spark.tc/

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