Thanks for the confirmation, Stephen.

On Tue, Mar 3, 2015 at 3:53 PM, Stephen Boesch <> wrote:
Thanks, I was looking at an old version of FileInputFormat..

BEFORE setting the recursive config (mapreduce.input.fileinputformat.input.dir.recursive)
scala> sc.textFile("dev/*").count Not a file: file:/shared/sparkup/dev/audit-release/blank_maven_build

The default is null/not set which is evaluated as "false":

scala> sc.hadoopConfiguration.get("mapreduce.input.fileinputformat.input.dir.recursive")
res1: String = null


Now set the value :

scala> sc.hadoopConfiguration.get("mapreduce.input.fileinputformat.input.dir.recursive")
res4: String = true


res5: Long = 3481

So it works.

2015-03-03 15:26 GMT-08:00 Ted Yu <>:

Looking at FileInputFormat#listStatus():

    // Whether we need to recursive look into the directory structure

    boolean recursive = job.getBoolean(INPUT_DIR_RECURSIVE, false);


  public static final String INPUT_DIR_RECURSIVE =



On Tue, Mar 3, 2015 at 3:14 PM, Stephen Boesch <> wrote:

The sc.textFile() invokes the Hadoop FileInputFormat via the (subclass) TextInputFormat.  Inside the logic does exist to do the recursive directory reading - i.e. first detecting if an entry were a directory and if so then descending:

     for (FileStatus globStatmatches) {
          if (globStat.isDir()) {
            for(FileStatus statfs.listStatus(globStat.getPath(),
                inputFilter)) {
          } else {

However when invoking sc.textFile there are errors on directory entries: "not a file". This behavior is confusing - given the proper support appears to be in place for handling directories.

2015-03-03 15:04 GMT-08:00 Sean Owen <>:
This API reads a directory of files, not one file. A "file" here
really means a directory full of part-* files. You do not need to read
those separately.

Any syntax that works with Hadoop's FileInputFormat should work. I
thought you could specify a comma-separated list of paths? maybe I am
imagining that.

On Tue, Mar 3, 2015 at 10:57 PM, S. Zhou <> wrote:
> Thanks Ted. Actually a follow up question. I need to read multiple HDFS
> files into RDD. What I am doing now is: for each file I read them into a
> RDD. Then later on I union all these RDDs into one RDD. I am not sure if it
> is the best way to do it.
> Thanks
> Senqiang
> On Tuesday, March 3, 2015 2:40 PM, Ted Yu <> wrote:
> Looking at scaladoc:
>  /** Get an RDD for a Hadoop file with an arbitrary new API InputFormat. */
>   def newAPIHadoopFile[K, V, F <: NewInputFormat[K, V]]
> Your conclusion is confirmed.

> On Tue, Mar 3, 2015 at 1:59 PM, S. Zhou <> wrote:
> I did some experiments and it seems not. But I like to get confirmation (or
> perhaps I missed something). If it does support, could u let me know how to
> specify multiple folders? Thanks.
> Senqiang

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